Can memcpy given value as source address in c
WebThe C library function void *memcpy (void *dest, const void *src, size_t n) copies n characters from memory area src to memory area dest. Declaration Following is the … WebMay 28, 2009 · which is actually just the reverse of the memcpy () you did to get the pointer there in the first place. Although, treating the pointer as an int: int addressOfArgTwo = (unsigned int)buff; is also dangerous, if you're moving between 32-bit and 64-bit architectures, as Michael pointed out. Pointers aren't always 32-bit integers.
Can memcpy given value as source address in c
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WebSo the answer is no; the check is not necessary (or yes; you can pass zero). Share Improve this answer Follow edited Sep 22, 2012 at 10:42 answered Sep 20, 2010 at 13:32 Mike Seymour 248k 28 442 637 1 Would a pointer be considered "valid" for purposes of such a function if it pointed to the location following the last element of an array? WebOct 21, 2014 · But memcpy () is about copying memory objects, not values. An object resides at a given address, and contains a given value. Taking n gives the value, …
WebFeb 16, 2013 · Your constant (macro) is really just a literal. As such, it has no address which could be given as parameter to memcpy or another function that expects a … WebApr 29, 2004 · Optimizing Memcpy improves speed. Knowing a few details about your system-memory size, cache type, and bus width can pay big dividends in higher performance. The memcpy () routine in every C …
WebAug 31, 2012 · On Linux, your fourth choice is to use FORTIFY_SOURCE. FORTIFY_SOURCE uses "safer" variants of high risk functions like memcpy, strcpy and gets. The compiler uses the safer variants when it can deduce the destination buffer size. If the copy would exceed the destination buffer size, then the program calls abort (). WebOct 11, 2024 · When you refer to the address of a pointer, this normally means the pointer's own location in memory, not the value it holds (which also is an address). – Andreas Wenzel Oct 11, 2024 at 4:55 1 @N001: If you follow the advice I gave in my first comment, does your program then work as intended? Both printed pointer values are the same, then.
WebOct 25, 2015 · Save it to a .c file, like test.c, and compile it using gcc, like this: It will (most likely) behave differently. Try replacing memcpy with strncpy and see what happen. I hope the example is useful. With memcpy, the destination cannot overlap the source at all. With memmove it can.
WebNov 27, 2024 · No, you can't [portably] use memset for that purpose, unless the desired target value is 0.memset treats the target memory region as an array of bytes, not an array of ints.. A fairly popular hack for filling a memory region with a repetitive pattern is actually based on memcpy.It critically relies on the expectation that memcpy copies data in … chillax server ipWebApr 1, 2011 · I am trying to write a stl vector in C, and I could do it if client allocating memory on the heap and pass as an element to me. But I want it to work with basic datatype and there should not be special way to pass variables on the stack or heap variables. – Avinash Apr 5, 2011 at 13:33 chillax plus charging timeWebNov 20, 2014 · If you have allocated using malloc you must state the size of the array. int * src = malloc (ARRAY_LENGTH*sizeof (*src)); int * dst1 = malloc … chillax shopWebApr 8, 2024 · You can certainly use memcpy (c1->ques, q1->ques, string_size). But it's non-standard for a string copy operation and reduces readability. – selbie Apr 8, 2024 at 3:35 Add a comment 1 In C parameters are passed by value rather than by reference. chillax party roomWebJun 4, 2013 · I need a function that stores data into a void pointer. Here is a simple example of it: void saveData (void* data) { char inputData [] = "some data"; memcpy ( (char*)data, inputData, sizeof (inputData)); } However I get segmentation errors when I do this, even though it compiles just fine. My function argument has to be a void pointer because I ... chillax refrigerationWebAug 3, 2015 · @PSkocik "Character type" is a term-of-art in the C standard which encompasses both single char objects and arrays of them (and probably some other stuff I don't remember off the top of my head). Regardless, the point is that char[4] and int are not compatible types and therefore you cannot use int* to access memory declared as … chillax reviewsWebJun 24, 2015 · no, it's like *ptr = value;. memcpy takes the address of both source and destination. value must have type char * and ptr have type char ** (although you could … grace church of mentor